70x^2-64x-3=0

Solution for 70x^2-64x-3=0 equation:

70x^2-64x-3=0

a = 70; b = -64; c = -3;
Δ = b2-4ac
Δ = -642-4·70·(-3)
Δ = 4936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4936}=\sqrt{4*1234}=\sqrt{4}*\sqrt{1234}=2\sqrt{1234}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-2\sqrt{1234}}{2*70}=\frac{64-2\sqrt{1234}}{140}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+2\sqrt{1234}}{2*70}=\frac{64+2\sqrt{1234}}{140}
$